-16x^2+98=0

Solution for -16x^2+98=0 equation:

-16x^2+98=0

a = -16; b = 0; c = +98;
Δ = b2-4ac
Δ = 02-4·(-16)·98
Δ = 6272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6272}=\sqrt{3136*2}=\sqrt{3136}*\sqrt{2}=56\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{2}}{2*-16}=\frac{0-56\sqrt{2}}{-32}
=-\frac{56\sqrt{2}}{-32}
=-\frac{7\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{2}}{2*-16}=\frac{0+56\sqrt{2}}{-32}
=\frac{56\sqrt{2}}{-32}
=\frac{7\sqrt{2}}{-4}
$